149. Diketahui fungsi f(π₯) = (1 β 6π₯) / (1 β 2π₯) , π(π₯) = π₯^2 β 3π₯ + 6 , dan β(π₯) = 2π₯ + 3 . Tentukan (β β π β π)(1)
a. 15
b. 25
c. 35
d. 45
e. 55
Jawaban :
f(π₯) = (1 β 6π₯) / (1 β 2π₯)
π(π₯) = π₯^2 β 3π₯ + 6
β(π₯) = 2π₯ + 3
(β β π β π)(1)
= h (g (f (1)))
sehingga perlu dihitung f(1) terlebih dahulu
f(1) = (1 β 6(1)) / (1 β 2(1))
f(1) = (1 - 6) / (1 - 2)
f(1) = - 5 / - 1
f(1) = 5
(β β π β π)(1)
= h (g (f (1)))
= h (g (5))
sehingga perlu dihitung g(5)
π(5) = (5)^2 β 3(5) + 6
g(5) = 25 - 15 + 6
g(5) = 10 + 6
g(5) = 16
selanjutnya,
(β β π β π)(1)
= h (g (f (1)))
= h (g (5))
= h (16)
β(π₯) = 2π₯ + 3
h(16) = 2(16) + 3
h(16) = 32 + 3
h(16) = 35
Jawaban : C
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