150. Diketahui fungsi 𝑓(𝑥) = −2𝑥 + 2 , 𝑔(𝑥) = √𝑥^2 , dan ℎ(𝑥) = 𝑥^2 + 2𝑥 + 1 . Tentukan (𝑔 ∘ ℎ ∘ 𝑓)(−2) !
a. 22
b. 32
c. 18
d. 17
e. 49
Jawaban :
𝑓(𝑥) = −2𝑥 + 2
𝑔(𝑥) = √𝑥^2
ℎ(𝑥) = 𝑥^2 + 2𝑥 + 1
(𝑔 ∘ ℎ ∘ 𝑓)(−2)
= g (h (f (-2 )))
maka perlu dihitung f(-2) terlebih dahulu
𝑓(-2) = −2(-2) + 2
f(-2) = 4 + 2
f (-2) = 6
selanjutnya,
(𝑔 ∘ ℎ ∘ 𝑓)(−2)
= g (h (f (-2 )))
= g(h (6))
sehingga, perlu dihitung h (6)
ℎ(𝑥) = 𝑥^2 + 2𝑥 + 1
h(6) = 6^2 + 2(6) + 1
h(6) = 36 + 12 + 1
h(6) = 49
selanjutnya,
(𝑔 ∘ ℎ ∘ 𝑓)(−2)
= g (h (f (-2 )))
= g(h (6))
= g(49)
𝑔(𝑥) = √𝑥^2
𝑔(49) = √(49)^2
g(49) = 49
Jawaban : E
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