37. Diketahui π(π₯) = 3π₯ + 1 dan π(π₯) = 2π₯ β 5. Rumus (π π π)β1(π₯) =
a. (π₯ + 10) / 6
b. (π₯ + 12) / 6
c. (π₯ + 13) / 6
d. (π₯ + 14) / 6
e. (π₯ + 15) / 6
Jawaban :
π(π₯) = 3π₯ + 1
π(π₯) = 2π₯ β 5
(π π π)(π₯) = f ( g(x))
(π π π)(π₯) = f (2x - 5)
(π π π)(π₯) = 3(2x - 5) + 1
(π π π)(π₯) = 6x - 15 + 1
(π π π)(π₯) = 6x - 14
(π π π)(π₯) = 6x - 14
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