Friday, March 1, 2024

Kisi Kisi PAT Matematika Kelas XI no 37

37. Diketahui 𝑓(π‘₯) = 3π‘₯ + 1 dan 𝑔(π‘₯) = 2π‘₯ βˆ’ 5. Rumus (𝑓 π‘œ 𝑔)βˆ’1(π‘₯) =

a. (π‘₯ + 10) / 6

b. (π‘₯ + 12) / 6

c. (π‘₯ + 13) / 6

d. (π‘₯ + 14) / 6

e. (π‘₯ + 15) / 6


Jawaban :

𝑓(π‘₯) = 3π‘₯ + 1

𝑔(π‘₯) = 2π‘₯ βˆ’ 5


(𝑓 π‘œ 𝑔)(π‘₯) = f ( g(x))

(𝑓 π‘œ 𝑔)(π‘₯) = f (2x - 5)

(𝑓 π‘œ 𝑔)(π‘₯) = 3(2x - 5) + 1

(𝑓 π‘œ 𝑔)(π‘₯) = 6x - 15 + 1

(𝑓 π‘œ 𝑔)(π‘₯) = 6x - 14


(𝑓 π‘œ 𝑔)βˆ’1(π‘₯) = ?

(𝑓 π‘œ 𝑔)(π‘₯) = 6x - 14

y = 6x - 14
6x = y + 14
x = (y + 14) / 6
f βˆ’1(y) = (y + 14) / 6
βˆ’1(x) = (x + 14) / 6

Jawaban : D

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