Matematika Peminatan Sukino Kelas XII
Limit Fungsi Aljabar dan Fungsi Trigonometri
TUPOK 1
Soal dan Pembahasan Matematika Sukino Peminatan
Bagian A
10.
lim (x + 2) → 0
(x2 - 4) tan (x + 2)
---------------------- =
sin2 (x + 2)
a. - ∞
b. - 4
c. - 3
d. 4
e. ∞
Jawaban : B
lim (x + 2) → 0
(x2 - 4) tan (x + 2)
---------------------- =
sin2 (x + 2)
lim (x + 2) → 0
(x- 2) (x + 2) tan (x + 2)
------- . -------- . ------------- =
1 sin (x + 2)sin (x + 2)
lim (x + 2) → 0
(x - 2)
misalkan :
a = x + 2
x = a - 2
lim a → 0
(a - 2 - 2) =
lim a → 0
(a - 4) = -4
No comments:
Post a Comment