Matematika Peminatan Sukino Kelas XII
Limit Fungsi Aljabar dan Fungsi Trigonometri
LKS 4
Soal dan Pembahasan Matematika Sukino Peminatan
Bagian B
3. Selesaikanlah.
a. lim x →∞ √x (√(6x + 3) - √(6x - 15) )
b. lim x →∞ √(x+ 2) (√(x + 4) - √(x - 2) )
Jawaban :
a. lim x →∞ √x (√(6x + 3) - √(6x - 15) )
lim x →∞ (√(6x2 + 3x) - √(6x2 - 15x) )
a = p = 6
b = 3
q = - 15
karena a = p
Limit = (3+15)/ 2√6
Limit = 18/2√6
Limit = 9/6 √6
Limit = 3/2 √6
b. lim x →∞ √(x+ 2) (√(x + 4) - √(x - 2) )
lim x →∞ (√(x2 + 6x + 8) - √(x2 - 4) )
a = p =1
b = 6
q = 0
Limit = 6/2√1
Limit = 3
lim x →∞ (√(6x2 + 3x) - √(6x2 - 15x) )
a = p = 6
b = 3
q = - 15
karena a = p
Limit = (3+15)/ 2√6
Limit = 18/2√6
Limit = 9/6 √6
Limit = 3/2 √6
b. lim x →∞ √(x+ 2) (√(x + 4) - √(x - 2) )
lim x →∞ (√(x2 + 6x + 8) - √(x2 - 4) )
a = p =1
b = 6
q = 0
Limit = 6/2√1
Limit = 3
>> soal no 4
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