Matematika Peminatan Sukino Kelas XII
Limit Fungsi Aljabar dan Fungsi Trigonometri
LKS 4
Soal dan Pembahasan Matematika Sukino Peminatan
Bagian B
3. Selesaikanlah.
a. lim x ββ βx (β(6x + 3) - β(6x - 15) )
b. lim x ββ β(x+ 2) (β(x + 4) - β(x - 2) )
Jawaban :
a. lim x ββ βx (β(6x + 3) - β(6x - 15) )
lim x ββ (β(6x2 + 3x) - β(6x2 - 15x) )
a = p = 6
b = 3
q = - 15
karena a = p
Limit = (3+15)/ 2β6
Limit = 18/2β6
Limit = 9/6 β6
Limit = 3/2 β6
b. lim x ββ β(x+ 2) (β(x + 4) - β(x - 2) )
lim x ββ (β(x2 + 6x + 8) - β(x2 - 4) )
a = p =1
b = 6
q = 0
Limit = 6/2β1
Limit = 3
lim x ββ (β(6x2 + 3x) - β(6x2 - 15x) )
a = p = 6
b = 3
q = - 15
karena a = p
Limit = (3+15)/ 2β6
Limit = 18/2β6
Limit = 9/6 β6
Limit = 3/2 β6
b. lim x ββ β(x+ 2) (β(x + 4) - β(x - 2) )
lim x ββ (β(x2 + 6x + 8) - β(x2 - 4) )
a = p =1
b = 6
q = 0
Limit = 6/2β1
Limit = 3
>> soal no 4
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