37. ഽ(1/(2x√x)) = ...
a. - 1/√x + C
b. - 1/x√x + C
c. 1/√x + C
d. - 2/√x + C
e. - 1/2√x + C
Jawaban :
ഽ(1/(2x√x))
= ഽ(1/(2x^(3/2))
= ഽ(1/2 . 1/x^(3/2))
= ഽ(1/2 . x^ - (3/2))
= 1/2 . (1 / (-3/2 + 1)) . x ^ (- 3/2 + 1) + C
= 1/2 . 1/(-1/2) . x^(-1/2) + C
= 1/2 . (-2) . x^ (-1/2) + C
= - x^(-1/2) + C
= - 1/x^1/2 + C
= - 1/√x + C
Jawaban : A
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