147. Diketahui π(π₯) = π₯^2 + 2π₯ β 3 dan g(π₯) = π₯ + 1 , tentukan (π β π)(β4) !
a. -22
b. 3
c. 12
d. 0
e. -13
Jawaban :
π(π₯) = π₯^2 + 2π₯ β 3
g(π₯) = π₯ + 1
g (- 4) = - 4 + 1
g (4) = - 3
(π β π)(β4)
= f (g(-4))
= f (-3)
= (-3)^2 + 2 (-3) - 3
= 9 - 6 - 3
= 9 - 9
= 0
(π β π)(β4) = 0
Jawaban : D
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