143. Tentukan invers dari π(π₯) = 8π₯ + 4 !
a. πβ1(π₯) = π₯ + 4
b. πβ1(π₯) = (π₯ β 4) / 8
c. πβ1(π₯) = π₯ β 4
d. πβ1(π₯) = (π₯ β 8) / 4
e. πβ1(π₯) = (βπ₯ β 4) / 8
Jawaban :
π(π₯) = 8π₯ + 4
y = 8x + 4
y - 4 = 8x
x = (y - 4) / 8
πβ1(y) = (y - 4) / 8
πβ1(x) = (x - 4) / 8
Jawaban : B
No comments:
Post a Comment