140. Diketahui π(π₯) = 3π₯^2 β 6 dan g (π₯)=12/(2π₯ + 1) . Tentukan hasil operasi (3π β π)(1) !
a. 10
b. -10
c. 13
d. -13
e. 23
Jawaban :
π(π₯) = 3π₯^2 β 6
g (π₯)=12/(2π₯ + 1)
(3π β π)(1) = 3f(1) - g(1)
maka hitung dulu 3f(1) dan g(1)
π(π₯) = 3π₯^2 β 6
f(1) = 3(1)^2 - 6
f(1) = 3 - 6
f(1) = - 3
3f(1) = 3 . (-3)
3f(1) = - 9
g (π₯)=12/(2π₯ + 1)
g (1) = 12 / (2 (1) + 1)
g (1) = 12 / (2 + 1)
g (1) = 12 / 3
g (1) = 4
sehingga
(3π β π)(1) = 3f(1) - g(1)
(3π β π)(1) = - 9 - 4
(3π β π)(1) = - 13
Jawaban : D
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