Matematika Peminatan Sukino Kelas XII
Limit Fungsi Aljabar dan Fungsi Trigonometri
LKS 2
Soal dan Pembahasan Matematika Sukino Peminatan
Bagian B
1. Tentukan nilai masing-masing limit fungsi trigonometri berikut.
a.
lim x→0
x . tan x
------------ =
1 - cos 3x
b.
lim x→0
1 - √cos x
------------ =
x2
c.
lim x→1
1 - x2
-------- =
sin πx
d.
lim x→1 (1 - x) tan (πx/2)
Jawaban :
a.
lim x→0
x . tan x
------------ =
1 - cos 3x
1 - cos 3x = 2 sin 3/2 x sin 3/2 x
lim x→0
x . tan x
------------------------ =
2 sin 3/2 x sin 3/2 x
1/2 . 2/3 . 2/3
= 2/9
------------------------------------------------------------------------------------------------------
b.
lim x→0
1 - √cos x
------------ =
x2
lim x→0
1 - √cos x 1 + √cos x
------------ . ------------- =
x2 1 + √cos x
lim x→0
1 - cos x 1
------------ . ------------- =
x2 1 + √cos x
1 - cos x = 2 sin 1/2 x sin 1/2 x
2 sin 1/2 x sin 1/2 x 1
----------------------- . ---------- =
x2 1 + √cos 02 . 1/2 . 1/2 . 1/2
= 1/4
------------------------------------------------------------------------------------------------------
c.
lim x→1
1 - x2
-------- =
sin πx
menggunakan turunan fungsi
lim x→1
- 2x
---------- =
π cos πx
- 2 . 1
------------ =
π cos π . 1
-2/(π . -1)
= 2/π
------------------------------------------------------------------------------------------------------
d.
lim x→1 (1 - x) tan (πx/2) =
lim x→1
(1 - x) . sin (πx/2) / cos (πx/2) =
lim x→1
sin (πx/2) . (1 - x) / cos (πx/2) =
sin (π/2) . lim x→1 (1 - x) / cos (πx/2) =
1 . lim x→1 (1 - x) / cos (πx/2) =
menggunakan turunan
lim x→1
- 1
-------------------- =
- sin (πx/2) . π/2
1 . 2/π
= 2/π
>> soal bag B no 2
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