Latihan Kompetensi Siswa 2
Kelas XI
SMA Kelas XI
Buku Sukino Kelompok Wajib
Kunci Jawaban Matematika Buku Sukino Kelas XI Kelompok Wajib
A.
15. Persamaan garis normal pada kurva y = x3 - 4x yang sejajar dengan garis x + 8y - 8 = 0 dan melalui titik yang berabsis positif adalah ...
a. x + 8y - 2 = 0
b. x + 4y + 130 = 0
c. x - 8y - 2 = 0
d. x - 4y + 130 = 0
e. x - 8y + 2 = 0
Jawaban : A
garis x + 8y - 8 = 0
cari gradien terlebih dahulu
8y = -x + 8
y = - 1/8x + 1
m = - 1/8
karena sejajar, maka gradien garis normal = m1 = - 1/8
gradien kurva :
m1 . m2 = - 1
- 1/8 . m2 = -1
m2 = 8
y = x3 - 4x
y ' = 3x2 - 4
m2 = 3x2 - 4
8 = 3x2 - 4
12 = 3x2
x2 = 4
x = 2 (karena absis positif)
nilai y ?
y = x3 - 4x
y = 23 - 4 . 2
y = 8 - 8
y = 0
titik potong (2,0)
persamaan garis normal :
y - y1 = m (x - x1)
y - 0 = - 1/8 (x - 2)
8y = - x + 2
x + 8y - 2 = 0
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