Buku Sukino
Matematika Peminatan
Kelas XII
Bab Aplikasi Turunan
LKS 2
17. Persamaan garis normal dari kurva g(x) = sin x / (1 + cos x) pada titik berabsis x = Ο/3 adalah ...
a. 6x + 9y = 2Ο + 3β3
b. 6x - 9y = 2Ο - 3β3
c. 9x + 6y = 3Ο + 2β3
d. 9x - 6y = 3Ο + 2β3
e. 9x + 6y = 3Ο - 2β3
Jawaban : C
g(x) = sin x / (1 + cos x)
u = sin x
u ' = cos x
v = 1 + cos x
v ' = - sin x
g'(x) = (cos x (1 + cos x) - sin x . (-sin x)) / (1 + cos x)2
g'(x) = (cos x + cos2 x + sin2 x) / (1 + cos x)2
sifat : cos2 x + sin2 x = 1
g'(x) = (cos x + 1) / (1 + cos x)2
g'(x) = 1 / (1 + cos x)
di titik berabsis x = Ο/3
g'(x) = 1 / (1 + cos x)
g'(x) = 1 / (1 + cos Ο/3)
g'(x) = 1/ (3/2)
g'(x) = 2/3
m garis normal = - 1 /(2/3) = - 3/2
cari nilai y dari x = Ο/3
g(x) = sin x / (1 + cos x)
g(Ο/3) = sin Ο/3 / (1 + cos Ο/3)
g(Ο/3) = 1/2β3 / (1 + 1/2)
g(Ο/3) = 1/2β3 / (3/2)
g(Ο/3) = 1/2β3 . 2/3
g(Ο/3) = 1/3 β3
titik : (Ο/3, 1/3 β3)
persamaan garis singgung :
y - y1 = m (x - x1)
y - 1/3 β3 = - 3/2(x - Ο/3)
y - 1/3 β3 = -3/2 x + Ο/2
6y - 2β3 = -9x + 3Ο
9x + 6y = 3Ο + 2β3
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