103. Invers dari fungsi π(π₯) = (β2 + 5π₯)/ (2 β 4π₯) adalah β¦
a. πβ1(π₯) = (β2π₯ β 2) / (β4π₯ β 5)
b. πβ1(π₯) = (2π₯ + 2) / (β4π₯ β 5)
c. πβ1(π₯) = (2π₯ + 2) / (4π₯ + 5)
d. πβ1(π₯) = (2π₯ β 2) / (4π₯ β 5)
e. πβ1(π₯) = (β2π₯ β 2) / (4π₯ + 5)
Jawaban :
π(π₯) = (β2 + 5π₯)/ (2 β 4π₯)
y = (β2 + 5π₯)/ (2 β 4π₯)
y (2 - 4x) = - 2 + 5x
2y - 4xy = - 2 + 5x
- 5x - 4xy = - 2 - 2y
x (- 5 - 4y )= - 2 - 2y
x = (- 2 - 2y) / (- 5 - 4y)
f (y) = ( - 2 - 2y) / (- 5 - 4y)
πβ1(π₯) = (- 2 - 2x) / (- 5 - 4x)
πβ1(π₯) = (- 2x - 2) / (- 4x - 5)
Jawaban : A
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