104. Diketahui f (π₯) = π₯^2 + 2 , dan π(π₯) = β2π₯ + 4. Tentukan nilai dari (π β π)(β1) adalah β¦
a. 40
b. 38
c. 36
d. 34
e. 32
Jawaban :
f (π₯) = π₯^2 + 2
π(π₯) = β2π₯ + 4
(π β π)(x) = f (g (x))
(π β π)(x) = f (- 2x + 4)
(π β π)(x) = (- 2x + 4)^2 + 2
(π β π)(x) = 4x^2 - 16x + 16 + 2
(π β π)(x) = 4x^2 - 16x + 18
(π β π)(β1) = 4(-1)^2 - 16(-1) + 18
(π β π)(β1) = 4(1) + 16 + 18
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