3. Selesaikan sistem persamaan berikut.
d.
2log (4 + x - 5y) = 0
2log (x + 1) = 1 + 2 2log y
Jawaban :
2log (4 + x - 5y) = 0
2log (4 + x - 5y) = 2log 1
4 + x - 5y = 1
x - 5y = - 3 ... (i)
x = - 3 + 5y
2log (x + 1) = 1 + 2 2log y
2log (x + 1) = 2log 2 + 2log y2
2log (x + 1) = 2log 2y2
x + 1 = 2y2
- 3 + 5y + 1 = 2y2
5y - 2 = 2y2
0 = 2y2 - 5y + 2
0 = (2y - 1)(y - 2)
maka
2y - 1 = 0
2y = 1
y = 1/2
atau
y - 2 = 0
y = 2
jika y = 1/2
maka
x = - 3 + 5y
x = - 3 + 5 . 1/2
x = - 3 + 5/2
x = - 1/2
jika y = 2
maka
x = - 3 + 5y
x = - 3 + 5 . 2
x = - 3 + 10
x = 7
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