Buku Matematika SMK Kelas X
Bab Trigonometri
Kasmina | Toali
39. Nilai dari tan 255Β° = ...
a. β3 + 2
b. 1 + 2β3
c. 3 + β2
d. 3 - β2
e. 2 - β3
Jawaban : C
tan 225 = tan (210 + 45)
tan 210 = tan (180 + 30) = tan 30 = 1/3 β3
tan 45 = 1
tan 225 = (tan 210 + tan 45) / (1 - tan 210 . tan 45)
tan 225 = (1/3 β3 + 1) / (1 - 1/3 β3 . 1)
tan 225 = (1/3 β3 + 1) / (1 - 1/3 β3) . (1 + 1/3 β3)/(1 + 1/3 β3)
tan 225 = (1/3 + 1 + 2/3 β3) / (1 - 1/3)
tan 225 = (4/3 + 2/3 β3) / (2/3)
tan 225 = 2 + β3
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