134. Panjang jari-jari lingkaran π₯^2 + π¦^2 β 4π₯ β 6π¦ + 4 = 0 adalah β¦ satuan.
a. 1
b. 2
c. 3
d. 4
e. 5
Jawaban :
π₯^2 + π¦^2 β 4π₯ β 6π¦ + 4 = 0
A = - 4
B = - 6
C = 4
jari jari lingkaran :
r = β((-1/2 A)^2 + (-1/2 B)^2 - C)
r = β((-1/2 . (-4))^2 + (-1/2 (-6))^2 - 4)
r = β((2)^2 + (3)^2 - 4)
r = β(4 + 9 - 4)
r = β9
r = 3 satuan
Jawaban : C
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