Matematika Sukino Kelas X
Bab 2 : Fungsi, Persamaan, dan Pertidaksamaan Logaritma
LKS 3
A.
3. Jika 2 . 3log y = 3log (x + 1) + 2, maka ...
a. y = x + 3
b. y = 3x + 3
c. y2 = - 9 (x + 1)
d. y2 = 9 (x + 1)
e. y2 = 3 (x + 1)
Jawaban : D
2 . 3log y = 3log (x + 1) + 2
3log y2 = 3log (x + 1) + 3log 32
3log y2 = 3log (x + 1) + 3log 9
3log y2 = 3log (9(x + 1))
y2 = 9 (x + 1)
> soal no 4
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