Friday, April 19, 2019

Jawaban Siap UNBK 2019 Ujian Nasional 2019 no 13

Jawaban Siap UNBK 2019 Ujian Nasional 2019
HOTS
(Higher Order Thinking Skills)
Program Studi Matematika IPA 2019
Persiapan Ujian Matematika IPA 2019
Jawaban Ujian Matematika IPA 2019

13. Diketahui segitiga siku-siku ABC dengan cos A = 24/25 (A dan B merupakan sudut lancip). Nilai dari (csc A + tan B) (1 - sin B) adalah ...

A. 24/24
B. 18/25
C. 7/25
D. 6/25
E. 4/25

Jawaban : C

cos A = 24/25
samping A= 24 = depan B
miring = 25
depan A = √625 - 576 = √49 = 7 = samping B

csc A = miring/depan = 25/7
tan B = depan B / samping B = 24/7
sin B = depan B / miring = 24 / 25

(csc A + tan B) (1 - sin B)
= (25/7 + 24/7) ( 1 - 24/25)
= 49/7 . 1/25
= 7/25
>> Soal 14

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