Simulasi Matematika IPS 2019 No 8

Simulasi Matematika IPS 2019

8. ₀∫¹(3x - 1)(x + 2) dx = ...

a. -1/2
b. 1/2
c. 3/2
d. 4
e. 6

Jawaban : C
₀∫¹(3x - 1)(x + 2)
= ₀∫¹(3x² + 6x - x - 2)
= ₀∫¹(3x² + 5x - 2)
= [x³ + 5/2 x² - 2x + c]₀¹
= (1³ + 5/2 1² - 2 . 1 + c) - (0³ + 5/2 0² - 2 . 0 + c)
= 1 + 5/2 - 2
= 7/2 - 2
= 3/2

>>>Soal Simulasi IPS No 9