73. Agar lingkaran 𝑥^2 + 𝑦^2 − 4𝑥 + 6𝑦 + 𝑚 = 0 berjari-jari 5, m haruslah sama dengan … .
A. -38
B. -12
C. 12
D. 25
E. 38
Jawaban :
persamaan lingkaran :
𝑥^2 + 𝑦^2 − 4𝑥 + 6𝑦 + 𝑚 = 0
A = - 4
B = 6
C = m
jari jari = 5 satuan
r = √((-1/2 A)^2 + (-1/2 B)^2 - C)
5 = √((-1/2 . (-4))^2 + (-1/2 (6))^2 - m)
5 = √((2)^2 + (-3)^2 - m)
5 = √(4 + 9 - m)
5 = √(13 - m)
25 = 13 - m
m = 13 - 25
m = - 12
Jawaban : B
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